Question

ajuda por favor na minha prova de matemática 9 ano

Answer 1

$\boxed{\begin{array}{lr} x^2-4x+5=0 \end{array}}$

Então;

$\boxed{\begin{array}{lr} \Delta= \end{array}}$

$\boxed{\begin{array}{lr} b^2-4.a.c \end{array}}$

a = 1

b = -4

c = 5

$\boxed{\begin{array}{lr} \Delta=b^2-4.a.c\\\Delta=(-4)^2-4.1.5\\\Delta=16 -20\\\Delta=-4\end{array}}$

Então usando essa formula

o valor de Delta = -4

Resposta Correta;

$\boxed{\begin{array}{lr} d)\ \Delta=-4\ \ \checkmark \end{array}}$

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