Question

ajuda por favor é muito importante para trabalho
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Answer 1

$2 {x}^{2} = \frac{2x}{3} + \frac{1}{6} \times (6) \\ 12 {x}^{2} = 4x + 1 \\ 12 {x}^{2} - 4x - 1 = 0 \\ a = 12 \\ b = - 4 \\ c = - 1 \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4 \times a \times c } }{2 \times a} \\ x = \frac{ - ( - 4) + - \sqrt{ {( - 4)}^{2} - 4 \times 12 \times ( - 1) } }{2 \times 12} \\ x = \frac{4 + - \sqrt{16 + 48} }{24} \\ x = \frac{4 + - \sqrt{64} }{24} \\ x = \frac{4 + - 8}{24} \\ x 1= \frac{4 + 8}{24} = \frac{12}{24} = \frac{1}{2} \\ x2 = \frac{4 - 8}{24} = \frac{ - 4}{24} = \frac{ - 1}{6}$

Conferindo:

(Usa-se o positivo)

$2( { \frac{1}{2} )}^{2} = \frac{2 \times \frac{1}{2} }{3} + \frac{1}{6} \\ 2 \times \frac{1}{4} = \frac{1}{3} + \frac{1}{6} \\ \frac{1}{3} \times 8 = \frac{8}{24} \\ \frac{1}{6} \times (4) = \frac{4}{24} \\ 2 \times \frac{1}{4} = \frac{8}{24} + \frac{4}{24} \\ \frac{2}{4} = \frac{12}{24} \div (2) \\ \frac{1}{2} = \frac{6}{12} \\ \frac{6}{12} \div (6) = \frac{1}{2} \\ \frac{1}{2} = \frac{1}{2}$