Question

AJUDA PLEASE $\frac{5}{4} y+\frac{1}{3} y-\frac{8}{9} y=$

Answer 1

$\frac{5}{4} y + \frac{1}{3} y - \frac{8}{9} y \\ \frac{5y}{4} + \frac{1y}{3} - \frac{8y}{9} \\ \frac{9 \times 5y} {9 \times 4} + \frac{12y}{36} - \frac{4 \times 8y}{4 \times 9} \\ \frac{45y}{36} + \frac{12y}{36} - \frac{32y}{36} \\ \frac{45y + 12y - 32y}{36} \\ \frac{25y}{36} \\ \frac{25}{36} y$