Question

AJUDA PFVRRR
Efetue:

2 - 3i/4 - 5i - 2+3i/4+5i

Answer 1

$\frac{2 - 3i}{4 - 5i} - \frac{2 + 3i}{4 + 5i} \\ \frac{(4 + 5i) \: . \: (2 - 3i) - (4 - 5i) \: . \: (2 + 3i)}{(4 - 5i) \: . \: (4 + 5i)} \\ \frac{8 - 12i + 10i - 15i {}^{2} - (8 + 12i - 10i - 15i {}^{2} )}{16 - 25i {}^{2} } \\ \frac{8 - 12i + 10i - 15 \: . \: ( - 1) - (8 + 12i - 10i - 15 \: . \: ( - 1))}{16 - 25 \: . \: ( - 1)} \\ \frac{8 - 12i + 10i + 15 - (8 + 12i - 10i + 15)}{16 + 25 } \\ \frac{8 - 12i + 10i + 15 - (23 + 2i)}{41} \\ \frac{8 - 12i + 10i + 15 - 23 - 2i}{41} \\ \frac{0 - 4i}{41} \\ \frac{ - 4i}{41} \\ \boxed{\boxed{\boxed{ - \frac{4}{41} i}}}$

att. yrz