Question

ajuda pf!
$3^{3x-1}. 9^{2x+3} = 27^{3-x}$

Answer 1

$3^{3x-1}.3^{2(2x+3)}=3^{3(3-x)}$

$3^{3x-1}.3^{4x+6}=3^{9-3x}$

$3^{3x}.3^-^1.3^{4x}.3^6=3^9.3^{3x}$

$3^{7x}.3^5=3^9.3^{3x}$

$3^{7x}\div3^{-3x}=3^9\div3^5$

$3^{10x}=3^4$

$10x=4$

$x= \frac{4}{10} =\fbox{ \frac{2}{5} }$