Question

Ajuda para resolver e desenvolver.
(1/3-2b)³

Answer 1

$(a + b)^3 = a^3 - 3a^2b + 3ab^2 - b^3$

$(\frac{1}{3}-2b)^3 = (\frac{1}{3})^3 - 3(\frac{1}{3})^2(-2b) + 3(\frac{1}{3})(-2b)^2 - (-2b)^3\\\\\\ (\frac{1}{3}-2b)^3 = \frac{1}{27} +\frac{2b}{3} + 4b^2 + 8b^3$