Question

AJUDA NOIS
Resolva a inequação de 1°grau a seguir:
$\frac{x-7}{2} + \frac{x+2}{3} \ \textless \ 16$

Answer 1

$\frac{x-7}{2} + \frac{x + 2}{3} \ \textless \ 16 \\ \frac{3x - 21 + 2x + 4}{6} \ \textless \ 16 \\ \\ \frac{5x - 17}{6} \ \textless \ 16 \\ 5x - 17 \ \textless \ 16.6 \\ 5x = 96 + 17 \\ x = \frac{113}{5} = 22,6$

Ou seja, x < 22,6