Question

ajuda nessa aqui por favor Mano.​

Answer 1

Resposta:

$a)\\\frac{\left(2\left(4x-3\right)\right)}{3}-\frac{\left(4\left(4x+5\right)\right)}{9}-\frac{\left(5\left(x-4\right)\right)}{6}=2\\\\\mathrm{Multiplicar\:pelo\:minimo\:multiplo\:comum=}18\\\\\frac{2\left(4x-3\right)}{3}\cdot \:18-\frac{4\left(4x+5\right)}{9}\cdot \:18-\frac{5\left(x-4\right)}{6}\cdot \:18=2\cdot \:18\\\\12\left(4x-3\right)-8\left(4x+5\right)-15\left(x-4\right)=36\\\\x-16=36\\\\x-16+16=36+16\\\\x=52$

$b)\\\\\frac{2x+5}{3}-\frac{4x-9}{6}=\frac{3-4x}{2}\\\\\mathrm{Multiplicar\:pelo\:minimo\:multiplo\:comum=}6\\\\\frac{2x+5}{3}\cdot \:6-\frac{4x-9}{6}\cdot \:6=\frac{3-4x}{2}\cdot \:6\\\\2\left(2x+5\right)-\left(4x-9\right)=3\left(-4x+3\right)\\\\19=-12x+9\\\\19-19=-12x+9-19\\\\0+12x=-12x-10+12x\\\\\frac{12x}{12}=\frac{-10}{12}\\\\x=-\frac{5}{6}$