Question

ajuda na última por favor

Answer 1

a) $\sqrt[3]{-\dfrac{1}{343}}=x$

$x=\dfrac{\sqrt[3]{-1}}{\sqrt[3]{343}}\\ \\ x=\dfrac{-1}{\sqrt[3]{7^{3}}}\\ \\ x=-\dfrac{1}{7}$


b) $\sqrt[3]{x-1}=4$

$x-1=4^{3}\\ \\ x-1=64\\ \\ x=64+1\\ \\ x=65$


c) $\sqrt[4]{x}=Z$

$x=Z^{4}$


d) $x^{4}=16$

$x=\pm \sqrt[4]{16}\\ \\ x=\pm \sqrt[4]{2^{4}}\\ \\ x=\pm 2\\ \\ x=2\;\;\text{ ou }\;\;x=-2$


e) $\sqrt[5]{x}=32$

$x=32^{5}\\ \\ x=33\,554\,432$


f) $\sqrt[3]{\dfrac{1}{27}}=x$

$x=\dfrac{\sqrt[3]{1}}{\sqrt[3]{27}}\\ \\ x=\dfrac{1}{\sqrt[3]{3^{3}}}\\ \\ x=\dfrac{1}{3}$