Question

ajuda galera estou precisando

Answer 1

Resposta:

Explicação passo-a-passo:

Temos que A = (aij)2x2 tal que aij = $\left \{ {{i^{2},<=>i\neq}j \atop {i+j,<=>i=j} \right.$

$A=\left[\begin{array}{ccc}a_{11} &a_{12} &\\a_{21} &a_{22} &\\\end{array}\right]$

a₁₁ = 1 + 1 = 2

a₁₂ = 1² = 1

a₂₁ = 2² = 4

a₂₂ = 2 + 2 = 4

$A=\left[\begin{array}{ccc}2&1&\\4&4&\\\end{array}\right]$

2)

a)

a11 = 3.1 + 1 = 4

a12 = 1 - 2.2 = -3

a13 = 1 - 2.3 = -5

a21 = 2 - 2.1 = 0

a22 = 3.2 + 2 = 8

a23 = 2 - 2.3 = -4

$A=\left[\begin{array}{ccc}4&-3&-5\\0&8&-5\\\end{array}\right]$

b)

a11 = 1 - 1 = 0

a12 = 2.1 = 2

a13 = 2.1 = 2

a14 = 2.1 = 2

a21 = 2.1 = 2

a22 = 2 - 2 = 0

a23 = 2.2 = 4

a24 = 2.2 = 4

a31 = 2.1 = 2

a32 = 2.2 = 4

a33 = 3 -  3 = 0

a34 = 2.3 = 6

a41 = 2.1 = 2

a42 = 2.2 = 4

a43 = 2.3 = 6

a44 = 4 - 4 = 0

$A=\left[\begin{array}{cccc}0&2&2&2\\2&0&4&4\\2&4&0&6\\2&4&6&0\end{array}\right]$

c)

a11 = 3

a12 = 0

a21 = 0

a22 = 3

a31 = 0

a32 = 0

a41 = 0

a42 = 0

$A=\left[\begin{array}{cc}3&0\\0&3\\0&0\\0&0\end{array}\right]$

d)

a11 = 3.1 - 1 + 2 = 4

a12 = 3.1 - 2 + 2 = 3

a13 = 3.1 - 3 + 2 = 2

a21 = 3.2 - 1 + 2 = 7

a22 = 3.2 - 2 + 2 = 6

a23 = 3.2 - 3 + 2 = 5

a31 = 3.3 - 1 + 2 = 10

a32 = 3.3 - 2 + 2 = 9

a33 = 3.3 - 3 + 2 = 8

$A=\left[\begin{array}{ccc}4&3&2\\7&6&5\\10&9&8\end{array}\right]$