Question

Ajuda em mat... Passo a passo, pf

Answer 1

$\dfrac{ \dfrac{3}{4} \times \left \{ \dfrac{1}{6}+\dfrac{5}{2} \times \left[ \dfrac{5}{9}-\dfrac{\dfrac{1}{4} \times \left( 2-\dfrac{2}{5}\right)}{\dfrac{3}{2} - \dfrac{3}{8}}\right] \right\} }{\left[\dfrac{2}{3}+3 \times \dfrac{\dfrac{1}{8}}{\dfrac{1}{2}+\dfrac{1}{4}}\right] \times \dfrac{3}{7}-\dfrac{1}{4} \times \left(1+\dfrac{1}{2}\right)}=$

$\dfrac{ \dfrac{3}{4} \times \left \{ \dfrac{1}{6}+\dfrac{5}{2} \times \left[ \dfrac{5}{9}-\dfrac{\dfrac{1}{4} \times \left( -\dfrac{8}{5}\right)}{\dfrac{12-3}{8}}\right] \right\} }{\left[\dfrac{2}{3}+3 \times \dfrac{\dfrac{1}{8}}{\dfrac{2+1}{4}}\right] \times \dfrac{3}{7}-\dfrac{1}{4} \times \dfrac{3}{2}}=$

$\dfrac{ \dfrac{3}{4} \times \left \{ \dfrac{1}{6}+\dfrac{5}{2} \times \left[ \dfrac{5}{9}-\dfrac{ -\dfrac{8}{20}}{\dfrac{9}{8}}\right] \right\} }{\left[\dfrac{2}{3}+3 \times \dfrac{\dfrac{1}{8}}{\dfrac{3}{4}}\right] \times \dfrac{3}{7}-\dfrac{3}{8}}=$

$\dfrac{ \dfrac{3}{4} \times \left \{ \dfrac{1}{6}+\dfrac{5}{2} \times \left[ \dfrac{5}{9}+\dfrac{64}{180}\right] \right\} }{\left[\dfrac{2}{3}+3 \times \dfrac{4}{24}\right] \times \dfrac{3}{7}-\dfrac{3}{8}}=$

$\dfrac{ \dfrac{3}{4} \times \left \{ \dfrac{1}{6}+\dfrac{5}{2} \times \dfrac{100+64}{180} \right\} }{\left[\dfrac{2}{3}+\dfrac{12}{24}\right] \times \dfrac{3}{7}-\dfrac{3}{8}}=$

$\dfrac{ \dfrac{3}{4} \times \left \{ \dfrac{1}{6}+\dfrac{820}{360}\right\} }{\left[\dfrac{16+12}{24}\right] \times \dfrac{3}{7}-\dfrac{3}{8}}=$

$\dfrac{ \dfrac{3}{4} \times \left \{ \dfrac{60+820}{360}\right\} }{\dfrac{28}{24} \times \dfrac{3}{7}-\dfrac{3}{8}}=$

$\dfrac{ \dfrac{3}{4} \times \dfrac{880}{360}}{\dfrac{84}{168}-\dfrac{3}{8}}=$

$\dfrac{\dfrac{2.640}{1.440}}{\dfrac{84-63}{168}}=\dfrac{\dfrac{2.640}{1.440}}{\dfrac{21}{168}}=\dfrac{443.520}{30.240}=\dfrac{132}{9}\\\\ \boxed{\boxed{=\dfrac{44}{3}}}$

Espero não ter errado alguma etapa e de ter ajudado.
Bons estudos!