Question

Ajuda?


a)√98+√200+√162=
b) √7500-√2450-√4500=
d) √17+ =4√17
e)√20+√5=

Answer 1

$a) \sqrt{98}+ \sqrt{200}+ \sqrt{162}=$

$\sqrt{2.7^2}+ \sqrt{2^3.5^2}+ \sqrt{2.3^2.3^2} }=$

$7 \sqrt{2}+10 \sqrt{2}+9 \sqrt{2}=26 \sqrt{2}$

b) $\sqrt{7500}- \sqrt{2450}- \sqrt{4500}= \sqrt{2^2.3.5^4}- \sqr \sqrt{2.5^2.7^2}- \sqrt{2^2.3^2.5^3}=$

$50 \sqrt{3}- 35 \sqrt{2}-30 \sqrt{5}=50.1,7 - 35.1,4-30.2,2=$

$85-49-66= -30$

d) $\sqrt{17} +4 \sqrt{17}= 5 \sqrt{17}$

e) $\sqrt{20} + \sqrt{5}= \sqrt{2^2.5}+ \sqrt{5}=2 \sqrt{5}+ \sqrt{5}=3 \sqrt{5}$