Question

ajuda?
(-5)^-3
√13^2
8^x^+2=256
15^-3=1
9^x=1/27

Answer 1

$(-5)^-^3= (- \frac{1}{5})^3= - \frac{1}{125}$

$\sqrt{13^2} = 13$

$8^{x+2} = 256--\ \textgreater \ (2^3) ^{x+2} = 2^8--\ \textgreater \ 2^{3x+6}=2^8$ --->bases iguais,iguala os expoentes

3x + 6 = 8 --> 3x = 2 --> x = 2/3

$15^{-3x}=1--\ \textgreater \ 15^-^3^x=15^0$ (bases iguais )
        -3x = 0 --> x = 0

$9^{x} = \frac{1}{27} --\ \textgreater \ (3^2)^x= \frac{1}{3^3}--\ \textgreater \ 3^2^x=3^-^3$ bases iguais
      2x = -3 --> x = - 3/2