Question

AJUDA!!! 

2x²+4x+12=0  
da qnt??? 

Answer 1

$2x^{2}+4x+12=0$

Dividindo todos os membros por 2:

$\dfrac{2x^{2}}{2}+\dfrac{4x}{2}+\dfrac{12}{2}=\dfrac{0}{2}~~~\therefore~~~\boxed{\boxed{x^{2}+2x+6=0}}$

$\Delta=b^{2}-4ac\\\Delta=2^{2}-4*1*6\\\Delta=4-24\\\Delta=-20\\\Delta=-1*4*5\\\sqrt{\Delta}=\sqrt{-1}*\sqrt{4}*\sqrt{5}\\\sqrt{\Delta}=i*2*\sqrt{5}\\\sqrt{\Delta}=2i\sqrt{5}$

$x=\dfrac{-b\pm\sqrt{\Delta}}{2a}~~\therefore~~\dfrac{-2\pm2i\sqrt{5}}{2*1}~~\therefore~~\boxed{-1\pm i\sqrt{5}}$


$x'=-1+i\sqrt{5}\\x''=-1-i\sqrt{5}$