Question

aImagine um quadrilátero ABCD. O ângulo A mede 2x+4. O ângulo B mede 2x. O ângulo C 2x-22. O ângulo D mede 4x-2. Determine a medida de cada ângulo. * A = 80°; B = 76°; C = 54° e D = 150° A = 80°; B = 66°: C = 64° e D = 150° A = 60°; B = 80°; C = 90° e D = 120° A = 55°; B = 95°; C = 50° e D = 95°

Answer 1

Resposta:

$\textsf{letra A}$

Explicação passo a passo:

$\mathsf{A = 2x + 4}$

$\mathsf{B = 2x}$

$\mathsf{C = 2x - 22}$

$\mathsf{D = 4x - 2}$

$\mathsf{A + B + C + D = 360\textdegree}$

$\mathsf{(2x + 4) + 2x + (2x - 22) + (4x - 2) = 360\textdegree}$

$\mathsf{10x - 20 = 360}$

$\mathsf{10x = 380}$

$\boxed{\boxed{\mathsf{x = 38\textdegree}}}$

$\mathsf{A = 2(38) + 4 = 76 + 4 = 80\textdegree}$

$\mathsf{B = 2(38) = 76\textdegree}$

$\mathsf{C = 2(38) - 22 = 76 - 22 = 54\textdegree}$

$\mathsf{D = 4(38) - 2 = 152 - 2 = 150\textdegree}$