Question

Aii esses sao os ultimos me ajudem !!

Answer 1

$c) 2x-1=x-10 \\ 2x-x=-10+1 \\ <strong>x=-9$

$d)4(2x-5)=3-(-2x+1) </strong>\\ 8x-20=6x-3 \\ 8x-6x=-3+20 \\ 2x=17 \\ x= \frac{17}{2} ou \\ <strong>x=8,5$

$e) \frac{x}{4} +2= \frac{x-3}{2};  </strong>\\ x+8=2x-6 \\ x-2x=-6-8 \\ -x=-10;(*-1) \\ <strong>x=10$

$f) \frac{4}{5} + \frac{x}{2} = \frac{x}{3} -1 </strong>\\ 24+15x=10x-30 \\ 15x-10x=-30-24 \\ 5x=-54 \\ <strong>x= \frac{-54}{5} ou \\ x=-10,8$

$g)x+3=2(x- \frac{1}{2})</strong> \\ 2x+6=4(2x-1) \\ 2x+6=8x-4 \\ 2x-8x=-4-6 \\ -6x=-10 \\ x= \frac{-10}{-6} \\ <strong>x= \frac{5}{3} ou \\ x=1,66...$

$\frac{3(x-4)}{9} -1=x- \frac{4-x}{6}</strong> \\ 6(2x-8)-18=18x-12-3x \\ 12x-48-18=18x-12-3x \\ 12x-18x+3x=-12+48+18 \\ -3x=54 \\ x= \frac{54}{-3} \\ <strong>x=-18$


E) mmc=4;
F) mmc=30;
G) mmc=2;
H) mmc=18