Question

agora,de maneira semelhante,determine a solução de cada equação.

a) x+7/6=11/2-5x/3

b) 3/2.(x/2 -2)=5.(x-4)+16

c) 2.(3x/8 -2)=3.(1-7x/4)-x

Answer 1

A)$x+\frac{7}{6} = \frac{11}{2} - \frac{5x}{3}$

$x+\frac{5x}{3} = \frac{11}{2} - \frac{7}{6}  => \frac{3x+5x}{3} = \frac{11 \times 6 - 7 \times 2}{6 \times 2}$

$\frac{7x}{3} = \frac{52}{12}  => 7x = \frac{52}{4} => 28x = 52 => x= \frac{52}{28}$

B)

$\frac{3}{2}(\frac{x}{2}-2)=5(x-4)+16$

$\frac{3x}{4}- \frac{-3}{2}  = 5x-20 +16$

$\frac{3x}{4} -5x = -4 +\frac{-3}{2}$

$\frac{-17x}{4} = \frac{-11}{2} => 17x= 44 => x=\frac{44}{17}$

C)

$2(\frac{3x}{8}-2) = 3(\frac{1-7x}{4})-x$

$\frac{3x}{4}-4 =  \frac{3-21x-4x}{4}$

$3x-16 = 3-25x => 28x=19 => x=\frac{19}{28}$