Question

adotando-se os valores log2=0,30 e log3=0,48, o logaritmo de 120 na base 5 vale:

Answer 1

log 5= log 10/2 = log 10 -log 2 =1-0,3=0,7


log 120= log 2³*5 *3 =log2³ + log 5 +log 3=3*log2+log 5+log 3= 0,9+0,7+0,48=2,08

log₅ 120 =log 120/log 5  = 2,08/0,7  ~  2,9714286