Question

adotando log3 =x e log5= y,entao o valor de log2,5 225 é igual a
a)2(x+y)/x-y
b)x+y/x-y
c)2(x-y)/x+y)​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log\:3 = x}$

$\mathsf{log\:5 = y}$

$\mathsf{log_{2,5}\:225 = \dfrac{log\:225}{log\:25/10}}$

$\mathsf{log_{2,5}\:225 = \dfrac{log\:(3.5)^2}{log\:(5^2/10)}}$

$\mathsf{log_{2,5}\:225 = \dfrac{2\:log\:3 + 2\:log\:5}{2\:log\:5 - log\:10}}$

$\boxed{\boxed{\mathsf{log_{2,5}\:225 = \dfrac{2(x + y)}{2y - 1}}}}$