Question

admitindo-se que Log5 2 = 0,43 e Log 5 3 = 0,68, obtém-se para log5 12 o valor

Answer 1

$\log_5(12) = \\\\ \log_5(6\times2) = \\\\ \log_5(6) + \log_5(2) = \\\\ \log_5(3\times2) + \log_5(2) = \\\\ \log_5(2) + \log_5(2) + \log_5(3) = \\\\ 2\log_5(2) + \log_5(3) = \\\\ 2(0,43) + 0,68 = \\\\ \boxed{1.54}$

Answer 2

$log_{5}12= log_{5}3.4 = log_{5}3+log_{5}4=log_{5}3+log_{5}2^{2} \\ \\ log_{5}3+2.log_{5}2=0,68+2.(0,43) = 0,68+0,86 = 1,54$

Espero ter ajudado.