Question

admitindo que log2= 0.3, log 3=0.48 e log 5=0.7 calcule o valor de√1200

Answer 1

Log√1200

= Log 1200^1/2
= 1/2 Log 1200
= 1/2 Log 2^4 * 3 * 5^2
= 1/2 Log2^4 + Log 3 + Log5^2
= 1/2 ( 4Log2 + Log3 + 2Log5)
= 1/2 (4*0,3 + 0,48 + 2*0,7)
= 1/2 (3,08)
= 1,54