Question

Admitindo log2= 0,3 e log3= 0,48, calcule os seguintes logaritimos

a) 6^x=8
b) 2^x=9
c) 3^x=9
d) 2^x=16

Answer 1

Resposta:

$6^x=8\\\\x\ln \left(6\right)=\ln \left(8\right)\\\\x=\frac{3\ln \left(2\right)}{\ln \left(6\right)}\\\\\\\\2^x= 9\\\\x\ln \left(2\right)=\ln \left(9\right)\\\\x=\frac{2\ln \left(3\right)}{\ln \left(2\right)}\\\\\\\\3^x=9\\\\3^2= ^(^3^*^3^) ^= ^9\\\\x =2\\\\\\\\2^x=16\\\\2^4=^(^4^*^4^=16$