Question

Admita que o log3= a+2 e log5=0,699, então podemos concluir que o log15 é:

Answer 1

log 15= log (3.5) = log 3 +log 5 = a+2 + 0,699 = a + 2,699

Answer 2

log15= log3+log5
log15=a+2+0,699= 2,699+a