Question

adicão e subtracão de fração com o mesmo denominador calcule
me ajudemmmmmmmmmmm​

Answer 1

Resposta:

$\frac{4}{ 3(2) } - \frac{2}{6(1)} = \frac{8}{6} - \frac{2}{6} = \frac{6}{6} = 1$

b)

$\frac{3}{4(3)} - \frac{2}{3(4)} = \frac{9}{12} - \frac{8}{12} = \frac{1}{12}$

c)

$\frac{2}{5((3)} - \frac{1}{3(5)} = \frac{6}{15} - \frac{5}{15} = \frac{1}{15}$

d)

$\frac{1}{2(3)} + \frac{1}{3(2)} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}$

e)

$\frac{1}{2(2)} + \frac{1}{4(1)} = \frac{2}{4} + \frac{1}{4} = \frac{3}{4}$

f)

$\frac{1}{3(4)} + \frac{1}{4(3)} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12}$

g)

$\frac{1}{3(2)} + \frac{5}{2(3)} = \frac{2}{6} + \frac{15}{6} = \frac{17}{6}$

h)

$\frac{6}{4(7)} - \frac{1}{7(4)} + \frac{1}{2(14)} = \frac{42}{28} - \frac{4}{28} + \frac{14}{28} = \frac{60 \div 4}{28 \div 4} = \frac{15}{7}$

i)

$\frac{2}{9(8)} + \frac{1}{8(9)} - \frac{1}{6(12)} = \frac{18}{72} + \frac{9}{72} - \frac{12}{72} = \frac{15 \div 3}{72 \div 3} = \frac{5}{24}$