Question

ache os dois zeros da funçao f(x) = x² - 10x + 24

Answer 1

Função Quadrática

Resolucionando por Bhaskara

• Coeficientes:

$\boxed{ \begin{array}{lr} \large \sf \: a = 1 \\ \large \sf \:b = - 10 \\ \large \sf \:c = 24 \end{array}}$

• Bhaskara:

$\boxed{ \begin{array}{lr} \\ \large \sf \: x = \dfrac{ - b \: \pm \: \sqrt{ {b}^{2} - 4ac } }{2.a} \\ \\ \\ \large \sf \: x = \dfrac{ - ( - 10) \: \pm \: \sqrt{ {10}^{2} - 4 \cdot1 \cdot24 } }{2.1} \\ \\ \\ \large \sf \: x = \dfrac{ 10\: \pm \: \sqrt{ 100 - 96 } }{2} \\ \\ \large \sf \: x = \dfrac{ 10\: \pm \: \sqrt{ 4 } }{2} \\ \\ \large \sf \: x = \dfrac{ 10\: \pm \: 2}{2} \\ \: \end{array}}$

• Raízes:

$\large \boxed{ \boxed{ \sf \: x_{1} = \dfrac{10 + 2}{2} = 6}} \\ \\ \large \boxed{ \boxed{ \sf \: x_{2} = \dfrac{10 - 2}{2} = 4}}$

➡️ Resposta:

$\huge \boxed{ \boxed{ \sf \: S = \{6 , 4\}}}$