Question

ache o x do vértice e o y do vértice da função $fx=-3(x+2)^2-1$, demonstre os passos.

Answer 1

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$f(x)=-3(x+2)^2-1 \\ f(x)=-3( x^{2} +4x+4)-1 \\ f(x)=-3 x^{2} -12x-12-1 \\ f(x)=- x^{2} -12x-13$

$a=-3 \\ b=-12 \\ c=-13 \\ \\ Xv=- \frac{b}{2a} = \frac{-(-12)}{2(-3)} = \frac{12}{-6} =-2$

$Yv=- \frac{\Delta}{4a} = \frac{-(-12)}{4(-3)} = \frac{12}{-12} =-1$

$\Delta=b^2-4ac \\ \Delta=(-12)^2-4(-3)(-13) \\ \Delta=144-156 \\ \Delta=-12$

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