Question

Ache o valor de y real sabendo-se que:
log2 y = log2 3 + log2 6 - 3.log2 4

Answer 1

$\log_{2}y=\log_{2}3+\log_{2}6-3.\log_{2}4$

$\log_{2}y=\log_{2}3.6-\log_{2} 4^{3}$

$\log_{2}y=\log_{2}18-\log_{2} 64$

$\log_{2}y=\log_{2} \dfrac{18}{64}$

$\log_{2}y=\log_{2} \dfrac{9}{32}$

$y=\dfrac{9}{32}$