Question

ache o resultafo da simplificação (2a+1)³-6a(2a+1)

Answer 1

(2a+1)³-6a(2a+1)
(2a+1)(2a+1)(2a+1)-6a.2a-6a
(4a²+4a+1)(2a+1)-12a²-6a
8a³+8a²+2a+4a²+4a+1-12a²-6a
8a³+12a²+6a+1-12a²-6a
Corta o -12a²+12a²=0
e o +6a-6a=0
fica
8a³+1

Answer 2

Olá Livia,


$\mathsf{(2a+1)^3-6a\cdot(2a+1)\Rightarrow (2a+1)\cdot[(2a+1)^2-6a]}\\=\\\mathsf{(2a+1)\cdot[4a^2+2a+2a+1-6a]\Rightarrow(2a+1)\cdot[4a^2-2a+1]}\\=\\\mathsf{(8a^3-4a^2+2a+4a^2-2a+1)\Rightarrow \boxed{\mathsf{(8a^3+1)}}}$

Dúvidas? comente