Question

Ache coordenadas de vertices da funcao -2x2-8x+10

Answer 1

Vamos là.

-2x² - 8x + 10

os coeficientes.

a = -2

b = -8

c = 10

delta

d = 64 + 80 = 144

vértice

Vx = -b/2a = 8/-4 = -2

Vy = -d/4a = -144/-8 = 18

V(-2, 18)

Answer 2

Explicação passo-a-passo:

-2x²-8x+10=0

a=-2

b=-8

c=10

∆=b²-4ac

∆=(-8)²-4*-2*10

∆=64+80

∆=144

Xv=-b/2a

Xv=8/2*-2

Xv=-8/4

Xv=-2

Yv=-∆/4a

Yv=-144/4*-2

Yv=-144/-8

Yv=144/8

Yv=18

S=>{ -2 e 18}