Question

ache as raízes da equação (×_3). (×+2)=_4​

Answer 1

$(x 3). (x+2)= 4\\\\3x^2+6x=4\\\\3x^2+6x-4=4-4\\\\3x^2+6x-4=0\\\\x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:3\left(-4\right)}}{2\times \:3}\\\\x_{1,\:2}=\frac{-6\pm \:2\sqrt{21}}{2\times \:3}\\\\x_1=\frac{-6+2\sqrt{21}}{2\times \:3},\:x_2=\frac{-6-2\sqrt{21}}{2\times \:3}\\\\x=\frac{-3+\sqrt{21}}{3},\:x=-\frac{3+\sqrt{21}}{3}$