Ache as medidas a.b.c.h.m.n.
Anexos:
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Soluções para a tarefa
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Para calcular a altura basta aplicar a seguinte fórmula 


.








=16.9=144
=
=12
Para achar que a hipotenusa(a) basta somar(m)+(n)=16+9=25
Para achar o cateto(b) basta aplicar a fórmula
=
(b)=
(a)=25
(n)=16
=25.9=225
=
=20
Para achar (c) basta aplicar a seguinte fórmula
=
(c)=
(a)=25
(m)=9
=25.9=225
=
=15
Resumindo:
(m)=9
(n)=16
(a)=25
(b)=20
(c)=15
Para achar que a hipotenusa(a) basta somar(m)+(n)=16+9=25
Para achar o cateto(b) basta aplicar a fórmula
(b)=
(a)=25
(n)=16
Para achar (c) basta aplicar a seguinte fórmula
(c)=
(a)=25
(m)=9
Resumindo:
(m)=9
(n)=16
(a)=25
(b)=20
(c)=15
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