Question

ache a raiz de x2-8x+7=0

Answer 1

x² - 8x + 7 = 0
Fatorando:
(x - 1)(x - 7) = 0

x - 1 = 0 --> x' = 1

x - 7 = 0 --> x'' = 7


S = {1 ; 7}

Answer 2

$x^{2} -8x+7=0$

Δ = b² - 4ac

Δ = (-8)² - 4 . 1 . 7

Δ = 64 - 28

Δ = 36

x = -b +- √Δ / 2a

x = 8 +- √36 / 2

x = 8 +- 6 / 2

x' = (8 + 6) / 2 = 7

ou

x" = (8 - 6) / 2 = 1