Question

ache a raiz da equação usando a fórmula de Bhaskara

c) x²-8x+7=0

Answer 1

$x^{2} -8x+7$

a=1

b=-8

c=7

Δ=$b^{2} -4.a.c$

Δ=$(-8)^{2} -4.1.7$

Δ=$64 -28$

Δ=$36$

$x1=\frac{-b+\sqrt{36}}{2.a} =\frac{-(-8)+6}{2.1} =\frac{+8+6}{2} =\frac{14}{2} =7$

$x2=\frac{-b-\sqrt{36}}{2.a} =\frac{-(-8)-6}{2.1} =\frac{+8-6}{2} =\frac{2}{2} =1$