Question

achar f(-1), f(0), f(1), f(2), f(3), f(4) se f(x)=x³-6x²+11x-6

Answer 1

f(-1)=-1+6-11-6=-12

f(0)=0+0+0-6=-6

f(1)=1-6+11-6=12-12=0

f(2)=8-24+22-6=30-30=0

f(3)=27-54+33-6=60-60=0

f(4)=64-96+44-6=108-102=6