Question

achar as raizes dos equação (x+3)2=1

Answer 1

Olá,

(x+3)² = 1
(x)²+2(x)(3)+(3)² = 1
x²+6x+9 = 1
x²+6x+9-1 = 0
x²+6x+8 = 0 sendo a = 1, b = 6 e c = 8

Δ = b²-4ac = (6)²-4(1)(8) = 36-32 = 4

x₁ = (-b+√Δ)/2a = (-6+√4)/2(1) = (-6+2)/2 = -4/2 = -2
x₂ = (-b-√Δ)/2a =(-6-√4)/2(1) = (-6-2)/2 = -8/2 = -4

Resposta:

As raízes são x₁ = -2 e x₂ = -4