Question

A x² + 5x + 6 = 0 B x² - 4x-5= 0 * Cx² - 6x - 16 = 0 Dx² - 4x – 60 = 0 Ex² + 1x – 12 = 0 *

Answer 1

FÓRMULA DO DELTA:

∆= b² - 4.a.c

FÓRMULA DE BHASKARA:

x= -b ± √∆ / 2.a

______________

a. x² + 5x + 6 = 0

∆= 5² - 4.1.6

∆= 25 - 24

∆= 1

x= -5±√1/2

x'= -5+1/2 = -4/2 = -2

x''= -5-1/2 = -6/2 = -3

b. x² - 4x - 5 = 0

∆=(-4)²- 4.1.(-5)

∆= 16 + 20

∆= 36

x= 4±√36/2

x'= 4+6/2 = 10/2 = 5

x''= 4-6/2 = -2/2 = -1

c. x² - 6x - 16 = 0

∆= (-6)² - 4.1.(-16)

∆= 36 + 64

∆= 100

x= 6±√100/2

x'= 6+10/2 = 16/2 = 8

x''= 6-10/2 = -4/2 = -2

d. x² - 4x - 60 = 0

∆= (-4)²-4.1.(-60)

∆= 16 + 240

∆= 256

x= 4±√256/2

x'= 4+16/2 = 20/2 = 10

x''= 4-16/2 = -12/2 = -6

e. x² + 1x - 12 = 0

∆= 1²- 4.1.(-12)

∆= 1 + 48

∆= 49

x=-1±√49/2

x'= -1+7/2 = 6/2 = 3

x''= -1-7/2 = -8/2 = -4

Espero ter ajudado:)