Question

a) x2 +5x +6 = 0
b) x2 - 3x +2 = 0
c) X2 - 8x +15 = 0
d) 3x² +4x +1 = 0
e) 12x +x-6 = 0
f) Y2 +94 + 14 = 0
g) ST2 - 9T + 4 = 0
h) 9Y2 -24y + 16 = 0
me ajudar por favor ​

Answer 1

Resposta:

Explicação passo-a-passo:

a) x² +5x +6 = 0

A=1, B=5, C=6

Δ=b²-4×a×c

Δ=(5)²-4×1×6

Δ=25-24

Δ=1

x=-b±√Δ / 2×a

x=-(5)±√1 / 2×1

x=5±1 / 2

x1=5+1/2

x1=6/2

x1=3

x2=5-1/2

x2=4/2

x2=2

b) x² -3x +2 = 0

A=1, B=-3, C=2

Δ=b²-4×a×c

Δ=(-3)²-4×1×2

Δ=9-8

Δ=1

x=-b±√Δ / 2×a

x=-(-3)±√1 / 2×1

x=3±1 / 2

x1=3+1/2

x1=4/2

x1=2

x2=3-1/2

x2=2/2

x2=1

c) X² - 8x +15 = 0

A=1, B=-8, C=15

Δ=b²-4×a×c

Δ=(-8)²-4×1×15

Δ=64-60

Δ=4

x=-b±√Δ / 2×a

x=-(-8)±√4 / 2×1

x=8±2 / 2

x1=8+2/2

x1=10/2

x1=5

x2=8-2/2

x2=6/2

x2=3

d) 3x² +4x +1 = 0

A=3, B=4, C=1

Δ=b²-4×a×c

Δ=4²-4×3×1

Δ=16-12

Δ=14