Question

a) x²+4x-5=0
b) x²+x - 6=0​

Answer 1

Resposta:

a)x²+4x-5=0

Delta =4²-4*1*-5

Delta=16+20

Delta=36, raiz de delta =6

$x1 = \frac{ - 4 + 6}{2 \times 1} = \frac{2}{2} = 1$

$x2 = \frac{ - 4 - 6}{2 \times 1} = \frac{ - 10}{2} = - 5$

b)x²+x-6=0

Delta=1²-4*1*-6

Delta=1+24

Delta=25, raiz de delta=5

$x1 = \frac{ - 1 + 5}{2 \times 1} = \frac{4}{2} = 2$

$x2 = \frac{ - 1 - 5}{2 \times 1} = \frac{ - 6}{2} = - 3$

Bons Estudos!!

Answer 2

Explicação passo-a-passo:

a) x2+4x-5=0

a= 1

b= 4

c= -5

Δ = b²-4 * a * c

Δ = 16 -4 * 1 * -5

Δ = 16 + 20 = 36

x = -b ±√Δ /2

x = -(4) ±√36 /2

x = -4 ±6 /2

( x=2/2 = 1 ) ou ( x= -10/2 = -5 )

b) x²+x-6=0

a= 1

b= 1

c= -6

Δ = b² -4 * a * c

Δ = 1 -4 * 1 * 1

Δ = -4

x = -1 ±√-4 /2