Question

a) x²-3x+2=0

b) 2y²-14y+12=0

Answer 1

x² - 3x + 2 = 0
a = 1; b = - 3; c = 2

Δ = b² - 4ac
Δ = (-3)² - 4.1.2
Δ = 9 - 8
Δ = 1

x = - b +/- √Δ
           2a

x = 3 + 1 = 4/2 = 2
         2

x = 3 - 1 = 2/2 = 1
        2
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b)
2y² - 14y + 12 = 0 (:2)
y² - 7y + 6 = 0

a = 1; b = - 7; c = 6

Δ = b² - 4ac
Δ = (-7)² - 4.1.6
Δ = 49 - 24
Δ = 25

x = - b +/- √Δ = - (-7) +/- √25
           2a                2.1

x = 7 + 5 = 12/2 = 6
      2

x = 7 - 5 = 2/2 = 1
        2