Question

a) x²-10x+25=0

b) 4y²-12y+8=0

respota urgente

Answer 1

a) a = 1 b = -10 c = 25
Δ = b² -4.a.c
Δ = (-10)² - 4 . 1 . 25
Δ = 100 - 100
Δ = 0

-b+ou-√Δ / 2 . a
₁ = -(-10) + 0 / 2 . 1
₁ = +10/2
₁ = 5
₂ = -(-10) - 0 / 2 . 1
₂ = 10/2
₂ = 5

b) a = 4 b = -12 c = 8
Δ = (-12)² - 4 . 4 . 8
Δ = 144 - 128
Δ = 16

-(-12) +ou-√16 / 2 . 4
₁ = 12 + 4 / 8 -> ₁ = 16/8 -> ₁ = 2
₂ = 12 - 4 / 8 -> ₂ = 8/8 -> ₂ = 1