Question

a)x+4(x-3)=x+2(x-3)
B)5+x-2(x+1)=5(1-x)
C)4+x-3(x+2)=6(3-x)+2-
d)8-x+4(x-2)=7(2-x)-5

Answer 1

em todas as questões aplica-se a distributiva:
A) x+4(x-3)=x+2(x-3)
   x+4x-12=x+2x-6
5x-12=3x-6
5x-3x=-6+12
2x=6
x=6/2
x=3

B)5+x-2(x+1)=5(1-x)
5+x-2x-2=5-5x
3-x=5-5x
-x+5x=5-3
3x=2
x=2/3

C) 4+x-3(x+2)=6(3-x)+2
4+x-3x-6=18-6x+2
-3x-2=20-6x
-3x+6x=20+2
3x=22
x= 22/3

D)8-x+4(x-2)=7(2-x)-5
8-x+4x-8=14-7x-5
3x=9-7x
3x+7x=9
10x=9
x=0,9

Answer 2

a) x+4x-12=x+2x-6
    x+4x-x-2x=-6+12
    2x = 6
      x = 6/3  x = 2
b) 5+x-2x-2=5-5x
    -x+5x = 5-5+2
    4x = 2
     x= 2/4    x = 1/2
c) 4+x-3x-6 = 18 -6x +2
    -2x+6x = 20-4+6
     4x = 22
      x = 22/4  x = 11/2
d) 8-x+4x-8 = 14 - 7x -5
    -x+4x+7x = 14-5-8+8
     10x = 9
         x=9/10