Question

a -x^4-x^2+6=0
b 35x^4 - 42x²+14=0
preciso do calculo tbm

Answer 1

a) -x^4 - x^2 + 6 = 0

-x² - x + 6 = 0

a = -1
b = -1
c = 6


Δ = b² - 4ac
Δ = (-1)² - 4 * (-1) * 6
Δ = 1 + 24
Δ = 25


x' = -b ± √Δ / 2a
x' = - (-1) ± √25 / 2 * (-1)
x' = 1 + 5 / (-2)
x' = 6/ (-2)
x' = -3


x" = 1 - 5 / (-2)
x" = -4/ (-2)
x" = 2




b) 35x^4 - 42x^2 + 14 = 0

35x² - 42x + 14 = 0

a = 35
b = -42
c = 14


Δ = b² - 4ac
Δ = (-42)² - 4 * 35 * 14
Δ = 1.764 - 1.960
Δ = 196



x' = -b ± √Δ / 2a
x' = - (-42) ± √196 / 2 * 35
x' = 42 + 14/ 70
x' = 56/70 : 2
x' = 28/35


x" = 42 - 14/70
x" = 28/70 : 7
x" = 4/10 : 2
x" = 2/5