Question

a) (x + 3)² + x² - 7
b) (x + 2)² = (x + 4 + 4x + 12​

Answer 1

Resposta:

a)

$( {x + 3)}^{2} + {x}^{2} - 7 = \\ {x}^{2} + 2(x)(3) + {3}^{2} + {x}^{2} - 7 = \\ {x}^{2} + {x}^{2} + 6x + 9 - 7 = \\ 2 {x}^{2} + 6x + 2$

b)

$( {x + 2)}^{2} = x + 4 + 4x + 12 = > \\ ( {x)}^{2} + 2(x)(2) + {2}^{2} = 5x + 16 \\ {x}^{2} + 4x + 4 = 5x + 16 = > \\ {x}^{2} + 4x - 5x + 4 - 16 = 0 = > \\ {x}^{2} - x - 12 = 0$

Bons Estudos!