Question

A) X+2y-z=0
3x-y+2z=1
2x+3y+z=7

B) X+y+z=2
2x+3y-2z=4
3x+4y-z=6​

Answer 1

Resposta:

A)

posto⁡ (0 1 2−1 |0 )

(3 0 −1 2 |1 ) =3

(2 0 3 1 |7 )

posto⁡ (0 1 2 −1 )

( 3 0 −1 2 ) =3

(2 0 3 1 )

solução geral :

10/11-7/11*z

-38/11+9/11*z

19/11+1/11*z

z

B)

posto:

(0 1 1 1 |2 )

(2 0 3 -2 |4 ) =3

(3 0 4 -1 |6 )

posto

( 0 1 1 1 )

( 2 0 3 -2 ) =3

( 3 0 4 -1 )

x=10/11−7/11⋅z

X=−38/11+9/11⋅z

y=19/11+1/11⋅z

z=z