Question

a)$\sqrt[3]{7+\sqrt{x-1} } =2$
b)$\sqrt{3x+\sqrt{x-4} } =4$
c)$\sqrt{x-\sqrt{25-x^{2} } } } =1$

Answer 1

Explicação passo-a-passo:

a) ³√(7 + √(x - 1)) = 2

(³√(7 + √(x - 1)))³ = 2³

7 + √(x - 1) = 8

√(x - 1) = 8 - 7

√(x - 1) = 1

(√(x - 1))² = 1²

x - 1 = 1

x = 1 + 1

x = 2

b) √(3x + √(x - 4)) = 4

3x + √(x - 4) = 16