Matemática, perguntado por km371282, 5 meses atrás

a)
 \frac{4}{7}   +  \frac{2}{7}
b
 \frac{9}{11}  -  \frac{2}{11}
c)
 \frac{5}{8}  +  \frac{3}{12}
d)
 \frac{5}{8}  +  \frac{1}{15}
e)
 \frac{2}{3}   + \frac{1}{2}
f)
5 +  \frac{2}{3}
g)
8 + 3. \frac{1}{5}
ultima h)
7 - 3(    \frac{5}{6}  \frac{2}{3})
jente me ajuda pfv preciso muito conto com vcs​

Soluções para a tarefa

Respondido por herick200266
1

Resposta:

Resposta:

a)

\frac{4}{7}+\frac{2}{7}\\

=\frac{4+2}{7}=\frac{6}{7}

b)

\frac{9}{11}-\frac{2}{11}

=\frac{9-2}{11}=\frac{7}{11}

c)

\frac{5}{8}+\frac{3}{12}

 =\frac{5}{8}+\frac{1}{4}=\frac{5}{8}+\frac{2}{8}=\frac{5+2}{8}=\frac{7}{8}

d)

\frac{5}{8}+\frac{1}{15}

=\frac{75}{120}+\frac{8}{120}=\frac{75+8}{120}=\frac{83}{120}

e)

\frac{2}{3}+\frac{1}{2}

=\frac{4}{6}+\frac{3}{6}=\frac{4+3}{6}=\frac{7}{6}

f)

5+\frac{2}{3}

5+\frac{2}{3}=\frac{15+2}{3}=\frac{17}{3}

g)

8+3\cdot \frac{1}{5}

=8+\frac{3}{5}=\frac{43}{5}=8,6

h)

7-3\left(\frac{5}{6}\cdot \frac{2}{3}\right)

=7-3\cdot \frac{5}{9}=7-\frac{5}{3}=\frac{16}{3}=5,333


km371282: obg
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