Question

A)
${7}^{2} + \sqrt{4 = }$
B)
$\sqrt{9} - \sqrt{4 = }$
c)
${3}^{3} \div {9}^{2} =$
d)
${3}^{2} + {3}^{1} - \sqrt{1} =$
e)
${5}^{2} + \sqrt{4} - {2}^{2} =$
f)
${10}^{1} + {3}^{0} - \sqrt{1 = }$

ajuda ai pfvr

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Answer 1

Resposta:

$7^2+\sqrt{4}=51\\\\\sqrt{9}-\sqrt{4}= 1\\\\3^3:9^2=\frac{1}{3}\\\\3^3+31-\sqrt{1}=57\\\\5^2+\sqrt{4}-2^2=23\\\\10^1+3^0-\sqrt{1}=10$