Question

a soma dos onze primeiros termos da p.g(2,4,8)

Answer 1

A1 = 2 q = 2 n = 11 An = A1 . q^n-1 An = 2 . 2^11-1 An = 2 . 2^10 An = 2 . 1024 An = 2048 Sn = A1 . (q^n - 1)/q-1 S11 = 2 . (2^11 - 1)/2-1 S11 = 2 . (2048 - 1)/1 S11 = 2 . 2047 S11 = 4094