Question

a soma dos infinitos termos da pg 1/3 , 1/6 , 1/12, ... e igual a

Answer 1

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Ola Alexandre 

PG

u1 = 1/3
u2 = 1/6

q = u2/u1 = (1/6)*(3/1) = 3/6 = 1/2

Soma infinita 

Sn = u1/(1 - q)
Sn = (1/3)/(1 - 1/2) = (1/3)/(1/2) = (1/3)*(2/1) = 2/3

pronto