Question

A soma de um número com sua metade é igual a 12. Que número é esse? *

( ) 2
( ) 4
( ) 8
( ) 16

Answer 1

$\large\boxed{\begin{array}{l}\sf A\,soma\,de\,um\,n\acute umero\,com\,sua\,metade\\\sf \acute e\,igual\,a\,12.Que\,n\acute um ero\,\acute e\,esse ?\\\sf()2\\\sf()4\\\sf(\bullet)8\\\rm()16\end{array}}$

$\large\boxed{\begin{array}{l}\rm n\acute umero\longrightarrow x\\\rm metade\,do\,n\acute umero:\dfrac{x}{2}\\\\\rm equac_{\!\!,}\tilde ao: x+\dfrac{x}{2}=12\\\underline{\sf soluc_{\!\!,}\tilde ao\!:}\\\rm x+\dfrac{x}{2}=12\bullet2\\\\\rm 2x+x=24\\\rm 3x=24\\\rm x=\dfrac{24}{3}\\\\\rm x=8\end{array}}$

Answer 2

✅ Após ter montado e resolvido a equação do primeiro grau, concluímos que o valor de "x" é:

       $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf x = 8\:\:\:}}\end{gathered} }$

Montando e resolvendo equação do primeiro grau:

       $\Large\displaystyle\begin{gathered}\tt x + \frac{x}{2} = 12 \end{gathered}$

     $\Large\displaystyle\begin{gathered}\tt \frac{2x + x}{2} = 12\end{gathered}$

     $\Large\displaystyle\begin{gathered}\tt 2x + x = 2\cdot12\end{gathered}$

             $\Large\displaystyle\begin{gathered}\tt 3x = 24\end{gathered}$

                $\Large\displaystyle\begin{gathered}\tt x = \frac{24}{3} \end{gathered}$

                $\Large\displaystyle\begin{gathered}\tt x = 8\end{gathered}$

✅ Portanto, o valor de "x" é:

                $\Large\displaystyle\begin{gathered}\tt x = 8\end{gathered}$

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